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Obama invited Saakashvili to the USA

2010-08-30 11:15

According to the press-service of Mikheil Saakashvili, the President of Georgia, received invitation to the special reception, organized by the U.S. leader Barack Obama for members of the UN General Assembly - RosBalt.

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Saakashvili is expected to meet with his counterparts from European, Latin American, African countries.  

According to previous messages, the Georgian president must deliver a speech at the 65th session of the UN GA in New-York.

Saakashvili will voice his speech in front of the UN on September 23rd, in the course of traditional common debates, planned in the session. 

The 65th session of the UN GA opens in New York on September 14th. Mikheil Saakashvili departs for America on September 20th.   

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